Outside of lecture and PeerWise, I made myself available to students via email and Monday drop-in hours. In my correspondence with students, I made a point of guiding students towards a better understanding rather than providing them with the exact answer, whether that was by sharing online resources or creating resources myself. In this section I have included a number of emails between myself and my students as well as the resources I created for those emails.
Hope you’re doing well!
I was just wondering if you would possibly be able to explain this question and why the indicated answer (3-methylheptane) has the chiral carbon but the two others do not. I’m just a bit confused.
Hi [Student 1],
If you recall, a chiral carbon is best defined as a carbon that has four different groups bonded to it in such a way that the mirror image cannot be superimposed on the original (refer to the following website for more information: http://www.chem.ucalgary.ca/courses/351/Carey5th/Ch07/ch7-3.html.)
Take a closer look at first two molecules and try to find the two similar groups that make the molecules achiral. I’ve attached videos revealing the answer to each molecule for your reference, as well as a video for extra practice.
Have fun studying this weekend, and remember to take breaks!
I’m having trouble understanding this question and how the answers were found. Do you mind helping me with it? Also, I have classes during your hours that’s why I can’t come.
Thank you so much,
Hi [Student 2],
I’d like to challenge you to try out the following simulation to see if it helps you make sense of concentration and dilution:
If you find the simulation does not help, I have attached a powerpoint “animation” to put the idea of concentration in terms you may understand. Feel free to email me again if these resources don’t provide you with enough information. My primary initiative is to guide you towards understanding, not just give you the answer straightaway.
Best wishes on the midterm!
Attached PowerPoint: Concentration and Dilution